4/(x^2-3x-4)

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Solution for 4/(x^2-3x-4) equation: 


D( x )

x^2-(3*x)-4 = 0

x^2-(3*x)-4 = 0

x^2-(3*x)-4 = 0

x^2-3*x-4 = 0

x^2-3*x-4 = 0

DELTA = (-3)^2-(-4*1*4)

DELTA = 25

DELTA > 0

x = (25^(1/2)+3)/(1*2) or x = (3-25^(1/2))/(1*2)

x = 4 or x = -1

x in (-oo:-1) U (-1:4) U (4:+oo)

4/(x^2-(3*x)-4) = 0

4/(x^2-3*x-4) = 0

x^2-3*x-4 = 0

x^2-3*x-4 = 0

DELTA = (-3)^2-(-4*1*4)

DELTA = 25

DELTA > 0

x = (25^(1/2)+3)/(1*2) or x = (3-25^(1/2))/(1*2)

x = 4 or x = -1

(x+1)*(x-4) = 0

4/((x+1)*(x-4)) = 0

4 = 0

x belongs to the empty set

x belongs to the empty set

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